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Discussion Starter · #1 ·
Electrical Experts...Please Help!

Tell me how I went wrong...

I wired up a relay from constant to momentary output today to allow for automatic door locking once the ignition is in the on position.

The relay worked just like it was supposed to when tested, but for some reason, it didn't work when I hooked it up to the driver door switch.

Lead 86 was fused from a switched ignition source in the drivers door.

Lead 85 was grounded with a 1K uf capacitor and 10K resistor wired in parallel, to allow for 1/2 second output. Had a diode between 85 and 86 as well...cathode was on same side as 86.

Lead 30 went to the negative (ground) door lock wire from the door lock switch

Lead 87 went to ground

I know that if you ground the door lock wire (black and white) located in the door lock switch, it will lock the doors. But for some reason the relay didn't want to work the way it was supposed to. I checked all the leads and I have power and ground...but the damn relay didn't want to work. :bash:

I tried another relay by itself, just to see if it would engage with my current leads, but it didn't work either, but when hooked up to the battery, it worked fine.

What is going on:dunno:
 

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Sounds like your design might be a little bit off. Try to explain what you're attempting to do with the diode, the capacitor, and the resistor cause I'm not immediately catching on.

I know that you somehow want the terminal 85 to be grounded for .5 second and then to float to some higher voltage level. Apparently, it's not being grounded at all if your relay never activates. Want to try a smaller resistor? What's the diode for?
 

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Discussion Starter · #3 ·
Originally posted by Bebber
Sounds like your design might be a little bit off. Try to explain what you're attempting to do with the diode, the capacitor, and the resistor cause I'm not immediately catching on.
I'm making the relay a momentary one by use of the above mentioned components, that way, it won't constantly transfer a signal (in my case, ground) to the door lock switch. "The capacitor allows the coil of the relay to be energized until the capacitor stores a charge, thus de-energizing the coil. The resistor bleeds off the charge of the capacitor when positive voltage is removed from the other side of the coil."

I think you may be right about the ground not being too good. I'm going to try and re-ground everything and see if it won't work...
 

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Fix all your problems quickly...Go buy an aftermarket alarm!lol!
 

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Discussion Starter · #5 ·
Originally posted by Number 3
Fix all your problems quickly...Go buy an aftermarket alarm!lol!
No need anymore! I already figured out the problem and corrected it. (Some minor re-wiring) I just need to wire up the relays, and I'm set!!!!!!

I'll keep you posted on my new AUTO LOCKS!
 
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